The current in an inductor is given by `i=alpha+betat` , where `t` is time. The self-induced emf in it is `V` . Find
(a) the self-inductance
(b) the energy stored in the inductor and the power supplied to it at time `t=t_(0)`

Explanation

(a) `e=-L(di)/(dt)`
`|e|=V=L(d)/(dt)(alpha+betat)`
(b) `U=(1)/(2)Li^(2)=(1)/(2).(V)/(beta)(alpha+betat_(0))^(2)`
At `t=t_(0)`
`P=ei=V(alpha+betat)`
At `t=t_(0)`
`=V(alpha+betat_(0))`