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A thin circular ring of area A is held p...

A thin circular ring of area A is held perpendicular to a uniform magnetic field of induction B. A small cut is made in the ring and a galvanometer is connected across the ends such that the total resistance of the circuit is R. When the ring is suddenly squeezed to zero area, the charge flowing through the galvanometer is

A

`(BR)/(A)`

B

`(BA)/(R)`

C

`ABR`

D

`(B^(2)A)/(R^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B
`Deltaq=(Deltaphi)/(R)=(BA)/(R)`
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CP SINGH-ELECTROMAGNETIC INDUCTION-EXERCISES
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  12. A short-circuited coil is placed in a time-varying magnetic field. Ele...

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  13. A uniform magnetic field B exists in a cylindrical region of radius I0...

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  14. A circular coil of radius 2.00cm has 50 turns. A uniform magnetic fiel...

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  15. A circular coil of one turn of radius 5.0cm is rotated about a diamete...

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  16. A magnet is brought towards a coil (i) speedily (ii) slowly then the i...

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  17. The flux linked with a circuit is given by phi=t^(3)+3t-7 . The graph ...

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  18. The magnetic flux (phi) linked with a coil depends on time t as phi=at...

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