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A conducting loop of cross-area A and re...

A conducting loop of cross-area `A` and resistance `R` is placed perpendicular to a magnetic field `B` . The loop is withdrawn completely from the field. The change, which flows through any cross-section of the wire in the process

A

`(B)/(R)`

B

`(BA)/(R)`

C

`(B)/(2R)`

D

`(2B)/(R)`

Text Solution

Verified by Experts

The correct Answer is:
B
`Deltaq=(Deltaphi)/(R)=(BA)/(R)`
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