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A conducting circular loop is placed in a uniform magnetic field `0.04T` with its plane perpendicular to the magnetic field. The radius of the loop starts shrinking at `2mm//sec` . The induced emf in the loop when the radius is `2cm` is

A

`3.2pimuV`

B

`4.8pimuV`

C

`0.8pimuV`

D

`1.6pimuV`

Text Solution

Verified by Experts

The correct Answer is:
A

`phi=BA=Bpir^(2)`
`e=(dphi)/(dt)=Bpi.2r(dr)/(dt)=0.04pixx2xx2xx10^(-2)xx2xx10^(-3)`
`=3.2pimuV`
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