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In the figure the flux through the loop ...

In the figure the flux through the loop perpendicular to the plane of the coil and direciton into the paper varying according to the relation `phi=6t^(2)+7t+I` where `phi` is in milliweber and `t` is in loop at `t=2s` and direction of induced current through `R` are

A

`39mV` , right to left

B

`39mV` , left to right

C

`31mV` right to left

D

`31mV` , left to right

Text Solution

Verified by Experts

The correct Answer is:
D
`phi=(6t^(2)+7t+1)xx10^(-3)`
`|e|=(dphi)/(dt)=(12t+7)xx10^(-3)`
At `t=2sec` , `|e|=31xx10^(-3)V`
`phi` is increasing with time, current will be anticlockwise.
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