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A square metal wire loop of side 10 cm a...

A square metal wire loop of side 10 cm and resistance 1 ohm is moved with a constant velocity `(v_0)` in a uniform magnetic field of induction `B=2 weber//m^(2)` as shown in the figure. The magnetic field lines are perpendicular to the plane to the loop (directed into the paper). The loop is connected to a network of resistors each of value 3 ohms. The resistances of hte lead wire OS and PQ are negligible. What should be the speed of the loop so as to have a steady current of 1 milliampere in the loop? Given the direction of current in the loop.

A

`0.5cm//sec`

B

`1cm//sec`

C

`2cm//sec`

D

`4cm//sec`

Text Solution

Verified by Experts

The correct Answer is:
C
Induced emf `e=Bvl`
`i=(Bvl)/(R_(eq))`
`10^(-3)=(2xxvxx0.1)/(4) implies v=2cm//sec`
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