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A player with 3 meter long iron rod run...

A player with 3 meter long iron rod runs toward east with a speed of `30km//hr` . Horizontal component of eath's magnetic field is `4xx10^(-5)Wb//m^(2)` . If he runs with the rod in horizontal and vertical position, then the potential difference induced between the two ends of the rod in the two cases will be

A

zero in vertical position, `1xx10^(-3)V` in horizontal position

B

`1xx10^(-3)V` in vertical position, zero in horizontal position

C

zero in both positions

D

`1xx10^(-3)V` in both positions

Text Solution

Verified by Experts

The correct Answer is:
B

`B_(h)=4xx10^(5)T` from south to north i.e.,
`vec(B)_(h)=4xx10^(-5)hatjT`
`vec(v)30xx(5)/(18)hati=(25)/(3)im//sec`
Horizontal Position: `vec(l)=3hatj` , `e=0`
Vertical position: `vec(l)=3hatk` , `e=B_(h)vl=4xx10^(-5)xx(25)/(3)xx3`
`=10^(-3)V`
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