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The loop shown moves with a velocity v i...

The loop shown moves with a velocity `v` in a uniform magnetic field of magnitude `B`, directed into the paper. The potential differene between point `P` and `Q` is e. Then

A

`(ii), (iii)`

B

`(i), (iv)`

C

`(i), (iii)`

D

`(ii), (iv)`

Text Solution

Verified by Experts

The correct Answer is:
C
`e=BLv`
`V_(p)+(e)/(4)-e+(e)/(4)=V_(Q)`
`V_(p)-V_(Q)=(e)/(2)=(BLv)/(2)` .
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