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In the previous question, in position I ...

In the previous question, in position `I` of the loop
(i) The induced emf will increases linearly as the loop enters the field
(ii) The induced emf will increase from `0` to `Bav` shaply as edge `BD` crosses `PQ`
(iii) The induced emf will have a constant value `Ba^(2)v`
(iv) The loop will experince a force to the left after entering the field partially

A

`(i), (iii)`

B

`(ii), (iii), (iv)`

C

`(i), (ii)`

D

`(ii), (iv)`

Text Solution

Verified by Experts

The correct Answer is:
D

`F=Bil`
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