A metal rod length l rotates about on end with a uniform angular velocity `omega`. A uniform magnetic field `vecB` exists in the direction of the axis of rotation. Calculate the emf induced between the ends of the rod. Neglect the centripetal force acting on the free electrons as they money in circular paths.

Options

A. `(BomegaL^(2))/(4)`
B. `(BomegaL^(2))/(2)`
C. `(3BomegaL^(2))/(4)`
D. `BomegaL^(2)`

Answer

B

Explanation

`de=Bvdx=Bomegaxdx` ltbr. `e=Bomegaint_(0)^(L)xdx=Bomega|(x^(2))/(2)|_(0)^(L)=(1)/(2)BomegaL^(2)` .