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A metal conductor of length 1m rotates v...

A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is `0.2xx10^(-4)T`, then the emf developed between the two ends of hte conductor is

A

`5mV`

B

`5xx10^(-4)V`

C

`50mV`

D

`50muV`

Text Solution

Verified by Experts

The correct Answer is:
D
`e=(1)/(2)B_(h)omegal^(2)=(1)/(2)xx0.2xx10^(-4)xx5xx1^(2)`
`e=50muV`
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