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Two coils have a mutual inductance 0.005...

Two coils have a mutual inductance `0.005 H`. The current changes in the first coil according to equation `I=I_(0)sin omegat`, where `I_(0)=10A` and `omega=100pi`radian//sec`. The maximum value of e.m.f. in the second coil is

A

`2pi`

B

`5pi`

C

`pi`

D

`4pi`

Text Solution

Verified by Experts

The correct Answer is:
B
`e=M(dI)/(dt)=MI_(0)omegacosomegat`
`e_(max)=MI_(0)omega=0.005xx10xx100pi=5pi`
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