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An ideal coil of 10 henry is joined in s...

An ideal coil of `10` henry is joined in series with a resistance of `5` ohm and a battery of `5` volt. `2` second after joining, the current flowing in ampere in the circuit will be

A

`e^(-1)`

B

`(1-e^(-1))`

C

`(1-e)`

D

`e`

Text Solution

Verified by Experts

The correct Answer is:
B
`i=(E)/(R)(1-e^(-(Rt)/(L)))=(5)/(5)(1-e^(-(5xx2)/(10)))=(1-e^(-1))`
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