A small object stuck on the surface of a glass sphere `(mu=4//3)` is viewed from the diametrically opposite position find transverse magnification.

Explanation

Refraction at 1,
`mu_1=(4)/(3),mu_2=1,u=-2R,R=-R,v=?`
`(mu_2)/(v)-(mu_1)/(u)=(mu_2-mu_1)/(R)`
`(1)/(v)-((4)/(3))/(-2R)=(1-(4)/(3))/(-R)`
`(1)/(v)+(2)/(3R)=(1)/(3R)`
`(1)/(v)=(1)/(3R)-(2)/(3R)=-(1)/(3R)`
`v=-3R`
`-ve` sign shows that image is formed at distance 3R. left of P.
Transverse magnification: `m=(mu_1v)/(mu_2u)=((4)/(3)(-3R))/((1)(-2R))`
`=2`