A poinit object `O` is placed in front of a glass rod having spherical end of radius of curvature `30cm`. The image would be formed at

Options

A. 30 cm left
B. infinity
C. 10 cm to the light
D. 18 cm to the left

Answer

A

Explanation

`(mu_2)/(v)-(mu_1)/(u)=(mu_2-mu_1)/(R)`
`((3)/(2))/(v)-(1)/(-15)=((3)/(2)-1)/(30)`
`(3)/(2v)+(1)/(15)=(1)/(60)implies(3)/(2v)=(1)/(60)-(1)/(15)=(1-4)/(60)=-(1)/(20)`