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What mass of Na(2)SO(4).7H(2)O contains ...

What mass of `Na_(2)SO_(4).7H_(2)O` contains exactly `6.023 xx 10^(22)` atoms of oxygen ? .

Text Solution

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Molar mass of `Na_(2) SO_(4).7H_(2)O = 275 gm`
`1` mole `Na_(2)SO_(4).7H_(2)O` has `11` mol `O` atoms
`rArr 11N_(A) O- "atoms are in" 275 g Na_(2)SO_(4).7H_(2)O`
`rArr 6.023 xx 10^(22) O -"atoms are in" =(275)/(11 xx 6.023 xx 10^(23)) xx 6.023 xx 10^(22) g = 2.5g` .
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