Home
Class 11
CHEMISTRY
A sample of MgSO(4) has 6.023 xx 10^(20...

A sample of `MgSO_(4)` has `6.023 xx 10^(20)O` atoms What is mass of `Mg` in sample ? .

Text Solution

Verified by Experts

In `MgSO_(4) ("mass of O")/("mass of Mg") = (16 xx 4)/(24) = (8)/(3)` = constant
Mass of `6.023 xx 10^(20)` O-atoms `= (6.023 xx 10^(20))/(6.023 xx 10^(23)) xx 16 = 16 xx 10^(-3) gms`
`rArr (8)/(3) = (16 xx 10^(-3))/("mass of Mg") rArr` Mass of Mg `= 6 xx 10^(-3)gms` .
Promotional Banner

Topper's Solved these Questions

  • MOLE CONCEPT

    ALLEN|Exercise EXERCISE - 01|49 Videos

  • MOLE CONCEPT

    ALLEN|Exercise EXERCISE - 02|46 Videos

  • IUPAC NOMENCLATURE

    ALLEN|Exercise Exercise - 05(B)|8 Videos

  • QUANTUM NUMBER & PERIODIC TABLE

    ALLEN|Exercise J-ADVANCED EXERCISE|26 Videos

Similar Questions

Explore conceptually related problems

A sample of MgSO_(4) contains 8 xx 10^(20) 'O' atoms what is the mass of 'S' in the sample ?

A sample of Na_2CO_(3) contains 6.02xx10^(23) of Na^(+) ions. The mass of the sample is ( at. Mass Na=23, C=12, O=16)

A pure sample of CaCO_(3) contain 100 moles of total atoms. What is the mass of sample-

A given sample of AlCl_3 contains 6.02 xx 10^20 Al^(3+) ions. The moles of Cl^- ions are

2.49 xx 10^(-18)g of an element X contains 2.0 xx 10^(4) atoms. What is the atomic mass of the element X ?

What mass of Na_(2)SO_(4).7H_(2)O contains exactly 6.023 xx 10^(22) atoms of oxygen ? .

The average translational K.E. of the molecules in a sample of oxygen at 300K is 6xx10^(-20)J . What is the average translational energy at 750 K?