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If 2.4gm Mg is treated with 0.64 gm O(2)...

If `2.4gm` Mg is treated with `0.64 gm O_(2)` Find composition of final product mixture ?
[Atomic Mass `Mg = 24]` .

Text Solution

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`{:(,Mg(s),+,(1)/(2)O_(2)(s),rarr,MgO(s)),(t=0,0.1mol,,0.2mol,,0),([O_(2)isLR],,,,,),(t=oo,0.1-0.02xx2,,0,,0.02xx2),(,=0.06mol,,=0.04mol,,):}` .
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