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0.41g of the silver salt of a dibasic or...

`0.41g` of the silver salt of a dibasic organic acid left a residue to `0.216` of silver on ignition. Calculate the molecular mass of the acid .

Text Solution

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Mass of the silver salt taken `(W) = 0.41g` Mass of Ag fromed `=0.216g`
`H_(2)Xrarrunderset(w=0.41g)(Ag_(2)X)rarrunderset(x=0.216g)(2Ag)`
Now malar mass acid `=n((108W)/(x)-107)gmol^(-1)=2((108xx0.41)/(0.216)-107)gmol^(-1)=196mol^(-1)`
Moleclar mass `= 196 g//mol` .
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