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Find final molarity in each case :...

Find final molarity in each case :

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`500ml " "0.1MHCl + 500 ml 0.2M HCl`
`M_(f) = (500 xx 0.1 + 500 xx 0.2)/(500 + 500) = 0.15 M`
(ii) `50 ml 0.1 M HCl +150ml " "0.3 MHCl+300ml H_(2)O`
`M_(f) = (50 xx 0.1 + 150 xx 0.3)/(50 + 150 + 300) = (50)/(500) = 0.1M`
(iii) `4.9g H_(2) SO_(4) + 250ml " "H_(2)O + 250 ml 0.1 M H_(2)SO_(4)`
`M_(f)=((4.9)/(98)+(250)/(1000)xx0.1)/(((250+250)/(1000)))=(50 + 25)/(500) = 0.15 M` .
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