How many grams of urea on heating yield `10^(22)` molecules of biuret by the reaction :
`2CO(NH_(2))_(2) rarr H_(2)N - CO - NH - CO - NH_(2) + NH_(3)` ?

Options

A. `1.495`
B. `0.995`
C. `1.99`
D. `1.753`

Answer

C

Explanation

`2Co(NH_(2))_(2)rarrNH_(2)-CO-NH-CO-NH_(2)`
`+6NH_(3)`
`2` molecule `larr 1` molecule
`(2)/(1)xx10^(22)` molecule `larr10^(22)`
mol `=(2xx10^(22))/(6.02xx10^(23))`
mass `=(2xx10^(22))/(6.02xx10^(23))xx60=1.99`