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Equal volume of 10% (v//v) of HCI is mix...

Equal volume of `10% (v//v)` of `HCI` is mixed with `10%(v//v) NaOH` solution. If density of pure `NaOH` is `1.5` times that of pure `HCl` then the resultant solution be ?

A

basic

B

neutral

C

acidic

D

can't be predicted.

Text Solution

Verified by Experts

The correct Answer is:
A

`10% (v//v) HCl`
`100ml` contain `10ml HCl`
`10% (v//v) NaOH` i.e. `100ml` contain `10mL NaOH` denisty of `NaOH=1.5` density of `NaOH =1.5` density of `HCl`
`((M)/(V))_(NaOH)= 1.5 ((M)/(V))_(HCl)`
Resultant = Basic
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