Solution containing `23 g HCOOH` is/are :

Options

A. `46 g` of `70% ((w)/(v)) HCOOH (d_("solution") = 1.40 g//mL)`
B. `50 g` of `10 M HCOOH (d_("solution") = 1 g//mL)`
C. `50 g` of `25% ((w)/(w)) = HCOOH`
D. `46 g` of `5" " M" "HCOOH (d_("solution") = 1 g//mL)`

Answer

A, B

Explanation

`(a)` In `100mL(140 g)` solution mass of solute
`= 70= (70)/(140)xx46=23 g`
`(b) 10M=("Mass of solute" //46)/((50)/(1xx1000))`
Mass of solute `=23 g`
`(c ) 100 g` solution contain `25 g` of solute mass of solute `=(25)/(100)xx50=12.5`
`(d) 5 M =("Mass of solute"//46)/(46//1000)`
Mass of solute `=10.58 g`