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Comprehension # 3 NaBr, used to produ...

Comprehension # 3
`NaBr`, used to produce `AgBr` for use in photography can be self prepared as follows :
`{:(,Fe+Br_(2)rarrFeBr_(2)," "..........(i),),(,FeBr_(2)+Br_(2)rarrFe_(3)Br_(8)," " ..........(ii) ," "("not balanced")),(,Fe_(3)Br_(8)+Na_(2)CO_(3)rarrNaBr+CO_(2)+Fe_(3)O_(4) , " ".......(iii)," "("not balanced")):}`
How much `Fe` in `kg` is consumed to produce `2.06xx10^(3) kg Nabr " "........(iv)`
Mass of iron required to produce `2.06xx10^(3) kg NaBr`

A

`10^(5) kg`

B

`10^(5) g`

C

`10^(3) kg`

D

none

Text Solution

Verified by Experts

The correct Answer is:
C
mole of `Fe_(3)Br_(8) = (100xx2.06xx10^(6))/(103xx70xx8)`
mole of Fe = mole `FeBr_(2) = (2.06xx10^(3)xx100xx100)/(103xx70xx60xx8)xx3`
mass of `Fe = (2.06xx10^(3)xx100xx100)/(103xx70xx60)xx56xx(3)/(8)`
mass of `Fe=10^(3) kg`
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