Find ratio of radius of `2^(nd)` orbit of `He^(+)` ion `& 3^(rd)` orbit of `Be^(+3)` ion.

Explanation

To find the ratio of the radius of the \(2^{nd}\) orbit of the \(He^{+}\) ion and the \(3^{rd}\) orbit of the \(Be^{+3}\) ion, we can use the formula for the radius of the \(n^{th}\) orbit in a hydrogen-like atom:

\[ r_n = 0.529 \times \frac{n^2}{Z} \text{ angstroms} \]

where:
- \(r_n\) is the radius of the \(n^{th}\) orbit,
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