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What is likely to be principal quantum n...

What is likely to be principal quantum number for a circular orbit of diameter `20nm` of the hydrogen atom if we assume Bohr orbit be the same as that represented by the principal quantum number?

A

`10`

B

`14`

C

`12`

D

`16`

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The correct Answer is:
B
`d=20nm`
`r=(20)/(2)=10nm=100Å`
`therefore r=0.529xx(n^(2))/(Z)A^(@)` For `H` atom `Z=1`
`100=0.529xxn^(2) " "n=14`
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