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In compound FeCl(2) the orbital angular ...

In compound `FeCl_(2)` the orbital angular momentum of last electron in its cation `&` magnetic moments (in Bohr Megneton) of this compound are :-

A

`(sqrt(6))h,sqrt(35)`

B

`(sqrt(6))h,sqrt(24)`

C

`0,sqrt(35)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B

`lambda=(h)/sqrt(2ME)" "lambdaprop(1)/sqrt(ME)`
`lambda_(e)prop(1)/sqrt(M^(e)xx16E) " "," "lambda_(p^(+))=(1)/sqrt(M_(p)xx4E)`
`lambda_(prop) prop (1)/sqrt(4M_(p)xx4E)" "," " "hence" lambda_(e)gtlambda_(p^(+))=lambda_(prop)`
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