Consider the following nuclear reactions involving X and Y.
`X rarr Y + ._(2)^(4)He`
`Y rarr ._(8)O^(18) + ._(1)H^(1)`
If both neutrons as well as protons in both the sides are conversed in nuclear reaction then moles of neutrons in 4.6 g on X :

Options

A. `3,2.4N_(A)`
B. `3,2.4`
C. `2,4.6`
D. `3,0.2N_(A)`

Answer

B

Explanation

`E = (hc)/(lambda) implies (1240)/(lambda_(nm))ev " "E=(1240)/(31)implies 40 eV`
`40=12.8 +K.E.`
`K.E. = 10-12.8=27.2eV`
`K.E. = 27.2 xx1.6xx10^(-19)`
`27.2 xx1.6xx10^(-19)=(1)/(2)xx9.1xx10^(-31)xxv^(2)`
`v = 2.18 xx sqrt(2) xx 10^(6) m//s`