Electronmagnetic radiations having `lambda=310Å`are subjected to a metal sheet having work function `=12.8eV`. What will be the velocity of photoelectrons with maximum Kinetic Energy….

Options

A. `0`, no emmision will occur
B. `2.18xx10^(6)m//s`
C. `2.18sqrt(2)xx10^(6)m//s`
D. `8.72xx10^(6)m//s`

Answer

C

Explanation

Frequency `=(1)/(T) prop (v)/(T) prop (ƶ//n)/(n^(2)//ƶ)`
Frequency `=(1)/(T) prop (ƶ^(2))/(n^(3))" "Tprop(n^(3))/(ƶ^(2))=(1//4)/(8//1) =(1)/(32)`