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The circumference of n^(th) orbit in H-a...

The circumference of `n^(th)` orbit in H-atom can be expressed in terms of deBroglie wavelength ` lambda` as :

A

`(0.529)nlambda`

B

`sqrt(nlambda)`

C

`(13.6)lambda`

D

`nlambda`

Text Solution

Verified by Experts

The correct Answer is:
D
`m_(y) = 0.25 m_(x), v_(y) = 0.75 v_(x)`
` lambda = (h)/(mv) " "lambda_(x) = (h)/(m_(x)v_(x)),lambda_(y)=(h)/(m_(y)v_(y))`
`lambda_(y)=(h)/(0.25M_(x)xx0.75v_(x)) " "lambda_(y)=5.33 A`
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