Wavelength of the Balmer H, line (first line) is `6565 Å`. Calculate the wavelength of `H_(beta)` (second line).

Answer

`4863 A^(@)`

Explanation

`n_(2)=3" "n_(1)=2` [first line]
`n_(2)=4" "n_(1)=2` [second line]
`(1)/(lambda)=R_(H)[(1)/(4)-(1)/(9)]`
`(1)/(6565)Å=R_(H)[(1)/(4)-(1)/(9)]....(i)`
`(1)/(lambda)=R_(H)[(1)/(4)-(1)/(16)]...(ii)" "((i))/((ii))`
`(lambda)/(6565)=((5)/(36))/((3)/(16))=(5xx16)/(36xx3)" "lambda=4863Å`