The velocity of `e^(-)` in a certain Bohr orbit of the hydrogen atom bears the ratio `1:275` to the velocity of light. What is the quantum no. "n" of the orbit and the wave no. of the radiation emitted for the transition form the quantum state `(n+1)` to the ground state.

Answer

`2;9.75xx10^(4)cm^(-1)`

Explanation

`V_(n)=2.18xx10^(6)xx(Z)/(n)=(2.18xx10^(6))/(n)`
`(2.18xx10^(6))/(n)=(1)/(275)`
`(2.18xx10^(6))/(n)=(1)/(3xx10^(8))=(1)/(275)`
`(2.18)/(n(300))=(1)/(275)" "(1)/(n)=(300)/(599.5)`
`n=(599.5)/(300)=(1)/(275)" "(1)/(n)=(300)/(599.5)`
`n=1.99~=2`