Calculate the velocity of an electron in the first Bohr orbit of a hydrogen atom

Answer

`6530xx10^(12)Hz`

Explanation

`V=(v)/(lambda)`
E pf Ist Bohr orbit `=-13.6`
`-13.6=(6.626xx10^(-34)xx3xx10^(8))/(lambda)`
or `-13.6=(1240)/(lambda("in nm"))`
`{:(lambda=(1240)/(136)xx10,|,V=(3xx10^(8))/(912xx10^(10)),),(lambda=91.17(nm),,,),(=912Å,=(3)/(912)xx10^(-R),,),(,=6530xx10^(12)Hz,,):}`