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The reaction between H(2) and Br(2) to f...

The reaction between `H_(2)` and `Br_(2)` to form `HBr` in presence of light is initiated by the photo decomposition of `Br_(2)` into free Br atoms (free radicals) by absorption of light. The bond dissociation energy of `Br_(2)` is `192kJ//"mole"`.What is the longest wavelength of the photon that would initiate the reaction?

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Verified by Experts

The correct Answer is:
`6235A^(@)`
`H_(2)+Br_(2)overset(hv)rarr2HBr`
`Br_(2)overset(hv)rarr2Br`
`BE=192kJ//"mole"`
`(192)/(93.368)eV//"mole"=(hc)/(hv)` or `(192)/(96.368)=(1240)/(lamda(nm))`
`lambda=6235Å`
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