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X-rays emitted from a copper target and ...

X-rays emitted from a copper target and a molybdenum target are found to contains a line of wavelength `22.85nm` attributed to the `K_(alpha)` line of an impurity element. The `K_(alpha)` lines of a copper `(Z=29)` and molybdenum `(Z=42)` have wavelength `15.42nm` and `7.12nm` respectively. Using Moseley's law, `gamma^(1//2)=a(Z-b)`. Calculate the atomic number of the impurity element.

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The correct Answer is:
`24`
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X-ray emitted from a copper target and a molybdenum target are found to contains a line of wavelength 22.85 n m attributed to the K_(alpha) line of an impurity element . The K_(alpha) line of copper (Z = 29) and molybdenum (Z = 42) have wavelength 15.42 nm and 7.12 nm , respectively. The atomic number of the impurity element is

The k_alpha X-rays of aluminium (Z = 13 ) and zinc ( Z = 30) have wavelengths 887 pm and 146 pm respectively. Use Moseley's law sqrt v = a(Z - b) to find the wavelength of the K_alpha X-ray of iron (Z = 26).

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The variation of wavelength lambda of the K_(alpha) line with atomic number Z of the target is shown by the following curve of

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