The linear charge density on a dielectric ring of radius `R` vanes with `theta` as `lambda = lambda_0 cos theta//2`, where `lambda_0` is constant. Find the potential at the center `O` of the ring [in volt].

The linear charge density on a ring of radius R is lambda=lambda_0 sin (theta) where lambda_0 is a constant and theta is angle of radius vector of any point on the ring with x-axis. The electric potential at centre of ring is

The linear charge density on a ring of radius R is lambda=lambda_0 sin (theta) where lambda_0 is a constant and theta is angle of radius vector of any point on the ring with x-axis. The electric potential at centre of ring is

A semicircular wire is uniformly charged with linear charge density dependent on the angle theta from y -direction as lambda=lambda_(0) |sin theta| , where lambda_(0) is a constant. The electric field intensity at the centre of the arc is

The linear charge density of a uniform semicircular wire varies with theta shown in the figure as lambda=lambda_(0)costheta if R is the radius of the loop ,of the charge on the wire is

A thin nonconducting ring of radius R has a linear charge density lambda = lambda_(0) cos varphi , where lambda_(0) is a constant , phi is the azimuthal angle. Find the magnitude of the electric field strength (a) at the centre of the ring , (b) on the axis of the ring as a function of the distance x from its centre. Investegation the obtained function at x gt gt R .

A thin nonconducting ring of radius R has a linear charge density lambda = lambda_(0) cos varphi , where lambda_(0) is a constant , phi is the azimutahl angle. Find the magnitude of the electric field strength (a) at the centre of the ring , (b) on the axis of the ring as a function of the distance x from its centre. Investegation the obtained function at x gt gt R .