An organic compound A has molecular formula `C_(10)H_(17)Br` and it is non-resolvable. A does not decolourize brown colour of bromine water solution. A on treatement with `(CH_(3))_(2 COK//(CH_(3))_(3)COH` yields `B` as majot product. B on treatment with `H_(2)//Pt` yields `(C_(10)H_(16))` which on treatment with `CI_(2)//hv` yields three monochloro derivative. Also B on boiling with acidic permanganate solution yields `C(C_(10)H_(16)O_(3))C`. on heating with sodalime yields `D(C_(9)H_(16)O).D` on reducing with `LiAIH_(4)` followed yields `C(C_(10)H_(16)O_(3)).C` on heating with sodalime yields `D(C_(9)H_(16)O).D` on reducing with `LiAIH_(4)` followed by heating product with concentrated `H_(2)SO_(4)` yields `E(C_(9)H_(16))` as major product. E on treatment with ozone followed by work-up with `Zn-H_(2)O` yields 6-Ketononanal.
Compound C is:

Options

A.
B.
C.
D.

Answer

A