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The reduction potential values are given...

The reduction potential values are given below
`AI^(3_)//AI =- 1.67 "volt" Mg^(2+)//Mg =- 2.34 "volt" Cu^(2+)//Cu = +0.34` volt
`I_(2)//2I^(-) = +0.53` volt. Which one is the best reducing agenet?

A

`AI`

B

`Mg`

C

`Cu`

D

`I_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Reducing agent, reduces other & get oxidized self higher negative value of `Mg^(2+)//Mg` indicates its tendency to get oxidized.
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ALLEN-ELECTROCHEMISTRY-Part (II) EXERCISE-01
  1. The oxidation potential of a hydrogen electrode at pH = 1 is (T = 298 ...

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  2. The electrode potential becomes equal to standard electrode potential ...

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  3. The reduction potential values are given below AI^(3)//AI =- 1.67 "v...

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  4. When iron is rusted, it is

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  5. The reference calomel electrode is made from which of the following ?

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  6. Given, standard electrode potentials, {:(Fe^(3+)+3e^(-) rarr Fe,,,E^...

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  7. The reduction potential of a hydrogen electrode at pH 10 at 298K is : ...

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  8. The emf of the cell, Ni|Ni^(2+)(1.0M)||Ag^(+)(1.0M)|Ag [E^(@) for Ni^(...

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  9. The position of some metals in the electrochemical series in dectreasi...

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  10. E^(@)(Ni^(2+)//Ni) =- 0.25 volt, E^(@)(Au^(3+)//Au) = 1.50 volt. The e...

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  11. When the electric current is passed through a cell having an electroly...

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  12. The oxidation ptentials of Zn, Cu, Ag, H2 and Ni are 0.76, - 34, - 0.8...

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  13. Which one of the following will increase the voltage of the cell ? (T...

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  14. A chemist wants to produce CI(2)(g) from molten NaCI. How many grams c...

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  15. Cosoder the reactopm: (T = 298 K) Cl2 (g) + 2 BR^(-) (aq) rarr 2 Cl^...

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  16. Three faradays of electricity qas passed through an aqueous solution o...

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  17. The standard emf for the cell cell reaction Zn + Cu^(2+) rarr Zn^(2+)...

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  18. Three moles of electrons are passed through three solutions in success...

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  19. The emf of the cell involving the following reaction, 2Ag^(+) +H(2) ra...

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  20. For the electrochemicl cell, M|M^(+)||X^(-)|X E((M^(+)//M))^(@) = 0.44...

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