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Given, standard electrode potentials, ...

Given, standard electrode potentials,
`{:(Fe^(3+)+3e^(-) rarr Fe,,,E^(@) = -0.036 " volt"),(Fe^(2+)+2e^(-)rarr Fe,,,E^(@) = - 0.440 " volt"):}`
The standard electrode potential `E^(@)` for `Fe^(3+) + e^(-) rarr Fe^(2+)` is :

A

`-0.476` volt

B

`-0.404` volt

C

`0.440` volt

D

`0.772` volt

Text Solution

Verified by Experts

The correct Answer is:
D
`Fe^(3+)+3e^(-)rarr Fe Delta G_(1)= -nF E_("cell")^(@)= -3F E_("cell")^(@)`
`Fe^(2+)+2e^(-)rarr Fe Delta G_(2)= - 2F E_("cell")^(@)`
`Fe^(3+)+e^(-)rarr Fe^(2+) Delta G_(3)= -F E_("cell")^(@)`
required `:' Delta G_(3) = Delta G_(1)-Delta G_(2)`
`-F E_("cell")= -3F E_("cell")^(@)+2F E_("cell")`
`-E_("cell")= -3xx(0.036)+2(-0.440)`
`-E_("cell")= -0.772` `E_("cell"= +0.772 V`
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