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For the electrochemicl cell, M|M^(+)||X^...

For the electrochemicl cell, `M|M^(+)||X^(-)|X E_((M^(+)//M))^(@) = 0.44 V` and `E_((X//X^(-)))^(@) = 0.33 V`
From this data one can deduce that :

A

`M +X rarr M^(+) +X^(-)` is the spontaneous reaction

B

`M^(+) +X^(-) rarr M +X` is the spontaneous reaction

C

`E_(cell) = 0.77V`

D

`E_(cell) = - 0.77V`

Text Solution

Verified by Experts

The correct Answer is:
B

For reaction (B)
`E_("cell")^(@)` values is positive hence it is spontaneous.
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For the electrochemical cell, M|M^(+) ||X^(-)|X , E_(M^(+)//M)^(@) = 0.44 V and E_(X//X^(-))^(@) = 0.33 V . From this data we can deduce that :

For the electrochemical cell (M|M^(+))|| (X^(-)|X) E^(@) (M^(+)//M) = 0.44V and E^(@) (X//X^(-))=0.33V From this data one can deduce that :

For the electrochemical cell, (M|M^(o+))||(X^(c-)|X),E^(c-)._((M^(o+)|M))=0.44V and E^(c-)._((X|X^(c-)))=0.334V

If E^(@)(M^(+)/M)= -0.44V and E^(@)(X/X^(-)) = 0.33V . From this data one can conclude that:

For the electrochemical cell, (M|M^(o+))||(X^(c-)|X) , E^(c-)._((M^(o+)|M))=0.44V , and E^(c-)._((X|X^(c-))=-0.33V . From this data, one can conclude that

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