Pt |{:((H(2))),(1atm):}:| pH = 2:|:|:pH ...

`Pt |{:((H_(2))),(1atm):}:| pH = 2:|:|:pH =3 |:{:((H_(2))Pt),(1atm):}:|`. The cell reaction for the given cell is:-

spontaneous

non-spontaneous

equilibrium

none is correct

Text Solution

Verified by Experts

The correct Answer is:

`E_("cell")=0.0591`
`(P_(H_(1))-P_(H_(2)))=0.0591(2-3)-0.0591`
= non-spontaneous

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