Home
Class 12
CHEMISTRY
A certain metal salt solution is electro...

A certain metal salt solution is electrolysed in series with a silver coulometer. The weight of silver and the metal deposited are `0.5094g` and `0.2653g`. Calculate the valency of the metal if its atomic weight is nearly that of silver.

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
B
`(w_(1))/(w_(2))=((E_(1))_(Ag))/((E_(2))_("metal"))` , `(0.5094)/(0.2653) = (((at.)/(v.f.))_(Ag))/(((at.)/(v.f.))_("metal"))`
`(0.5094)/(0.2653)=((v.f)_(Ag))/(1)` , `v.f. = 1.0~~2`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE-02|36 Videos

  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE-03|24 Videos

  • ELECTROCHEMISTRY

    ALLEN|Exercise INTEGER TYPE|18 Videos

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|483 Videos

  • HYDROCARBON

    ALLEN|Exercise MCQ|15 Videos

Similar Questions

Explore conceptually related problems

A certain metal salt solution is electrolysed in series with a silver coulometer. The weights of silver ad the metal deposited are 0.5094 g and 0.2653 g. Calculate the valency of the metal if its atomic weight is nearly that of silver.

A certain metal salt solution is electrolysed in series with a silver coulometer. The weights of silver and the metal deposited are 0.5094 g and 0.2653 g. Calculate the valency of the metal if its atomic weight is nearly that of silver.

The solution of a salt of a metal of atomic mass 112 was electrolysed for 15 minutes with a current of 1.5 ampere. The mass of the metal deposited was 0.788 g. Find the valency of the metal.

A solution of a salt of a metal was electrolysed for 150 minutes with a current of 0 . 15 amperes. The weight fo metal deposted was 0. 783 g . The equivalent weight to the metal is .

3.0 g of metal chloride gave 2.0 g of metal. Calculate the equivalent weight of the metal.

1.0 g of a metal oxide gave 0.2 g of metal. Calculate the equivalent weight of the metal.

ALLEN-ELECTROCHEMISTRY-Part (II) EXERCISE-01
  1. For the net cell reaction of the cell Zn(s) |Xn^(2+) ||Cd^(2+) |Cd(s) ...

    Text Solution

    |

  2. How many faraday are required to reduce one mol of MnO(4)^(-) to Mn^(2...

    Text Solution

    |

  3. Cu^(+) + e rarr Cu, E^(@) = X(1) volt, Cu^(2+) + 2e rarr Cu, E^(@) =...

    Text Solution

    |

  4. Zn|Zn^(2+)(c(1)) || Zn^(2+)(c(2))|Zn. For this cell DeltaG is negative...

    Text Solution

    |

  5. Pt(H(2))(p(1))|H^(o+)(1M)|(H(2))(p(2)),Pt cell reaction will be exergo...

    Text Solution

    |

  6. Pt |{:((H(2))),(1atm):}:| pH = 2:|:|:pH =3 |:{:((H(2))Pt),(1atm):}:|. ...

    Text Solution

    |

  7. M^(2+) +2e rarr M. 0.275 g of metal M is deposited at the cathode due ...

    Text Solution

    |

  8. In an electrochemical cell that function as a voltaic cell:-

    Text Solution

    |

  9. A certain metal salt solution is electrolysed in series with a silver ...

    Text Solution

    |

  10. The cell Pt(H(2))(1atm) |H^(+) (pH =?) T^(-) (a=1)AgI(s), Ag has emf, ...

    Text Solution

    |

  11. Using the information in the preceding problem, calculate the solubili...

    Text Solution

    |

  12. If same quantity of electricity is passed through CuCI and CuSO(4) the...

    Text Solution

    |

  13. For Zn^(2+) //Zn, E^(@) =- 0.76, for Ag^(+)//Ag, E^(@) = -0.799V. The...

    Text Solution

    |

  14. The oxidation potential of a hydrogen electrode at pH = 10 and P(H(2))...

    Text Solution

    |

  15. If x is specific resistance of the electrolyte solution and y is the m...

    Text Solution

    |

  16. E^(@) (SRP) of different half cell given {:(E(Cu^(2+)//Cu)^(@) =0.34...

    Text Solution

    |

  17. The conductivity of a saturated solution of Ag(3)PO(4) is 9 xx 10^(-6)...

    Text Solution

    |

  18. A saturated solution in AgA (K(sp)=3xx10^(-14)) and AgB (K(sp)=1xx10^(...

    Text Solution

    |

  19. An aqueus solution of NA(2)SO(4) was electrolysed for 10 min. 82 ml of...

    Text Solution

    |

  20. Na-Amalgam is prepared by electrolysis of aq. NaCI solution using 10gm...

    Text Solution

    |