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The e.m.f of the following cell Ni(s)/...

The e.m.f of the following cell
`Ni(s)//NiSO_(4)(1.0M) ||H^(+)(1.0M)|H_(2)(1atm), Pt` at `25^(@)C` is `0.236V`. The electrical energy which can be product is

A

`22.73 kJ`

B

`45.55 kJ`

C

`19.30 kJ`

D

`23.60kJ`

Text Solution

Verified by Experts

The correct Answer is:
B
`Ni(s) +2H_(2) rarr NiSO_(4) +H_(2)`
`0.236 = E^(@) - (0.0591)/(n)log.(1)/(1)`
`-nFE^(@) = DeltaG^(@)`
`DeltaG^(@) =- 2 xx 96500 xx 0.236 = 45.55 kJ`
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