Home
Class 12
CHEMISTRY
Consider the following Galvanic cell:- ...

Consider the following Galvanic cell:-

By what value the cell voltage when concentration of ions in anodic and cathodic compartments both increased by factor of 10 at 298K:

A

`+0.0591`

B

`-0.0591`

C

`-0.1182`

D

0

Text Solution

Verified by Experts

The correct Answer is:
C
`{:("Anode":, H_(2) rarr 2H^(+) +2e^(-)),("Cathode":,CI_(2)+2e^(-) rarr 2CI^(-)):}`
`E = E^(@) - 0.0591 log [H^(+)] [CI^(-)]`
on increasing concentration by 10 E wil increase by a factor of `-0.0591log 100 =- 0.0591 xx 2`
`=- 0.1182 V`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE-03|24 Videos

  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE-04 [A]|56 Videos

  • ELECTROCHEMISTRY

    ALLEN|Exercise Part (II) EXERCISE-01|44 Videos

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|483 Videos

  • HYDROCARBON

    ALLEN|Exercise MCQ|15 Videos

Similar Questions

Explore conceptually related problems

The Nernst equation: Consider the following galvanic cell Pb(s) | Pb^(2+)(aq.) || Ag^(2+)(aq.) | Ag(s) (a) What is the quantitative change in the cell voltage on increas-ing the ion concentrations in the anode compartment by a factor of 10 ? (b) What is the quantitative change in the cell voltage on increas-ing the ion concentration in the cathode compartment by a factor of 10 Strategy: The conventional notation of the cell tells us that lead is the anode while silve is the cathode. Therfore, the cell reaction is Pb(s) + 2Ag^(+)(aq.) rarr Pb^(2+)(aq.) + 2Ag(s) The cell potantial (at 25^(@)C ) is given by the Nernst equation, where n = 2 and Q = C_(Pb^(2+))//C_(Ag^(+)) : E_("cell") = E_("cell")^(@)-(0.0592 V)/(n) "logQ" E_("cell")^(@)-(0.0592 V)/(n) "logQ" C_(Pb^(2+))/C_(Ag^(+))^(2)

Write the Nernst equation for the cell reaction in the Daniel cell. How will the E_("cell") be affected when concentration of Zn^(+) ions is increased?

Consider the following relations for emf of a electrochemical cell (i) emf of cell = (Oxidation potential of anode)-(Reduction potential of cathode) (ii) emf of cell = (Oxidation potential of anode)+(Reduction potential of cathode) (iii) emf of cell = (Reduction potential of anode)+(Reduction potential of cathode) (iv) emf of cell = (Oxidation potential of anode)-(Oxidation potential of cathode) Which of the above realtions are correct?

ALLEN-ELECTROCHEMISTRY-EXERCISE-02
  1. The reduction potential of a half-cell consisting of a Pt electrode im...

    Text Solution

    |

  2. Consider the cell |{:(H(2)(Pt)),(1atm):} :|: {:(H(3)O^(+)(aq)),(pH =5....

    Text Solution

    |

  3. Hg(2)CI(2) is produced by the electrolytic reduction of Hg^(2+) ion in...

    Text Solution

    |

  4. The ionization constant of a weak electrolyte is 2.5 xx 10^(-5), while...

    Text Solution

    |

  5. Which of the following curve represents the variation of lambda(M) wit...

    Text Solution

    |

  6. Four moles of electrons were transferred from anode to cathode in an e...

    Text Solution

    |

  7. Equivalent conductance of BaCI(2),H(2)SO(4) & HCI at infinite are A(oo...

    Text Solution

    |

  8. Salts of A (atomic weight 7), B (atomic weight 27) and C (atomic weigh...

    Text Solution

    |

  9. Durinh electrlysis of an aqueous solution of CuSO(4) using copper elec...

    Text Solution

    |

  10. The cost at 5 paise/KWH of operating an electric motor for 8 hours whi...

    Text Solution

    |

  11. When an aqueous solution of LiCl is electrolyzed using graphite electr...

    Text Solution

    |

  12. A silver wire dipped in 0.1M HCI solution saturated with AgCI develops...

    Text Solution

    |

  13. Consider the reaction fo extraction of gold from its ore Au +2CN^(-)...

    Text Solution

    |

  14. Consider the following Galvanic cell:- By what value the cell vol...

    Text Solution

    |

  15. For the fuel cell reaction 2H(2)(g) +O(2)(g) rarr 2H(2)O(l), Deta(f)H(...

    Text Solution

    |

  16. The resistance of 0.5M solution of an electrolyte in a cell was found ...

    Text Solution

    |

  17. The dissociation constant of n-butyric acid is 1.6 xx 10^(-5) and the ...

    Text Solution

    |

  18. A graph was plotted between the molar conductance of various electroly...

    Text Solution

    |

  19. Starting with 250 ml of Au^(3+) solution 250 ml of Fe^(2+) solution, t...

    Text Solution

    |

  20. The following data rae obtained in an experiment {:("Solution", "Con...

    Text Solution

    |