The equivalent conductances of an infinitely dilute solution `NH_(4)CI` is 150 and the ionic conductances of `OH^(-)` and `CI^(-)` ions are 198 and 76 respectively. What will be the equivalent conductance of the solution of `NH_(4)OH` at infinite dilution. if the equivalent conductance of a `0.01N` solution `NH_(4)OH` is `9.6, what will be its degree of dissociation.

Answer

`272,0.0353`

Explanation

`Lamda_(NH_(4)Cl)^(@) = lamda_(NH_(4)^(+))^(@)+lamda_(Cl^(-))^(@)`
`:. lamda_(NH_(4)^(+))^(@) =Lamda _(NH_(4)Cl)^(@) -lamda_(Cl^(-))^(@)=150 -76 =74`
`:. Lamda_(NH_(4)OH)^(@) =lamda_(NH_(4)^(+))^(@) + lamda_(OH^(-))^(@) =74 +198 =272`
Further,
`= (9.6)/(272)=0.0353`.