When a solution of conductanes `1.342 mho m^(-1)` was placed in a conductivity cell with parallel electrodes the resistance was found to be `170.5` ohm. The area of the electrode is `1.86 xx 10^(-4)` sq meter. Calculate the distance between the two electrodes in meter.

Answer

`4.25 xx 10^(-2)` metres

Explanation

`(l)/(A) = R xx K`
`l =1.86 xx10^(-4) xx170.5 xx 1.342 =425 xx 10^(-4)`
`=4.25 xx 10^(-2)` meter.