3A current was passed through an aqueous solution of an unknown salt of `Pd` for 1hr. `2.977 g` of `Pd^(+n)` was deposited at cathode. Find n.

Answer

`n =4`

Explanation

`Pd^(+n) +nE rarr Pd`
`n_(Pd) = (2.977)/(106.4)`
`n_(Pd) = 0.028`
`n_(E) = 0.028 xx n`
`= (0.0238 xx n xx 96500)/(3600) =3 [1=(q)/(t)]`
`n = 4`