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The e.m.f. of the cell obtained by combi...

The e.m.f. of the cell obtained by combining `Zn` and `Cu` electrode of a Daniel cell with N calomel electrode in two different arrangements are `1.083V` and `0.018V` respectively at `25^(@)C`. If the standard reduction potential of N calomel electrode is `0.28V` find the emf og Daniel cell.

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The correct Answer is:
`E = 1.1V`
`E_(cell) = E_(ZN//Zn^(2+)) +E_(calomel(Red))`
`E_(ZN//Zn^(2+)) = 0.803`
`E_(cell) = E_(Cu^(2+)//Cu)`
`E_(cell) = 1.1V`
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ALLEN-ELECTROCHEMISTRY-EXERCISE-04 [A]
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  7. Calculate the EMF of a Daniel cell when the concentartion of ZnSO(4) a...

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  9. The EMF of the cell M|M^(n+)(0.02M) ||H^(+)(1M)|H(2)(g) (1atm)Pt at 25...

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  13. The cell Pt, H(2) (1atm) H^(+) (pH =x)| Normal calomel Electrode has a...

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  14. Estimate the cell potential of a Daniel cell having 1.0 M Zn^(++) and ...

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  15. Consider the cell AG|AgBr(s)|Br^(-)||AgCI(s)|CI^(-)|Ag at 25^(@)C. The...

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  16. The pK(sp) of AgI is 16.07 if the E^(@) value for Ag^(+)//Ag is 0.7991...

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