In two vessels each containing 500 ml water, 0.5m mol of aniline (`K_(b)=10^(-9))` and 25 m mol of HCl are added separately. Two hydrogen electrodes are constructed using these solutions. Calculate the emf of cell made by connecting them appropriately.

Answer

`E = 0.395V`

Explanation

For aniline
`K_(b) = calpha^(2)`
`10^(-9) = 10^(-3) alpha^(2)`
`alpha^(2) = 10^(-6)`
`alpha = 10^(-3)`
`[OH]^(-) = 10^(-3) xx 10^(-3) = 10^(-6)`
`[H^(+)] = 10^(-8)`
`[H^(+)] = (25)/(500)`
`[H^(+)] rArr 5 xx 10^(-2)`