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Calculate the e.m.f. of the cell Pt|H(...

Calculate the e.m.f. of the cell
`Pt|H_(2)(1.0atm)|CH_(3)COOH (0.1M)||NH_(3)(aq,0.01M)|H_(2)(1.0atm)|Pt`
`K_(a) (CH_(3)COOH) =1.8 xx 10^(-5), K_(b),(NH_(3)) = 1.8 xx 10^(-5)`

Text Solution

Verified by Experts

The correct Answer is:
`-0.46V`
`E_(Cell) = 0.0591 log.(|H^(+)|_(base))/(|H^(+)|_(add))`
`E_(cell) =- 0.0591 log. (10^(-14))/(10^(-2)sqrt(1.8 xx 10^(-3)))`
`(10^(-14))/((10^(-2)sqrt(1.8 xx 10^(-3)))/(10^(-1)sqrt(1.8 xx 10^(-4))))`
`E_(cell)=- 0.46V`
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